Merge pull request #511 from negativeExponent/updates
[pcsx_rearmed.git] / deps / crypto / base64.c
CommitLineData
ce188d4d 1/*********************************************************************
2* Filename: base64.c
3* Author: Brad Conte (brad AT bradconte.com)
4* Copyright:
5* Disclaimer: This code is presented "as is" without any guarantees.
6* Details: Implementation of the Base64 encoding algorithm.
7*********************************************************************/
8
9/*************************** HEADER FILES ***************************/
10#include <stdlib.h>
11#include "base64.h"
12
13/****************************** MACROS ******************************/
14#define NEWLINE_INVL 76
15
16/**************************** VARIABLES *****************************/
17// Note: To change the charset to a URL encoding, replace the '+' and '/' with '*' and '-'
18static const BYTE charset[]={"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/"};
19
20/*********************** FUNCTION DEFINITIONS ***********************/
21BYTE revchar(char ch)
22{
23 if (ch >= 'A' && ch <= 'Z')
24 ch -= 'A';
25 else if (ch >= 'a' && ch <='z')
26 ch = ch - 'a' + 26;
27 else if (ch >= '0' && ch <='9')
28 ch = ch - '0' + 52;
29 else if (ch == '+')
30 ch = 62;
31 else if (ch == '/')
32 ch = 63;
33
34 return(ch);
35}
36
37size_t base64_encode(const BYTE in[], BYTE out[], size_t len, int newline_flag)
38{
39 size_t idx, idx2, blks, blk_ceiling, left_over, newline_count = 0;
40
41 blks = (len / 3);
42 left_over = len % 3;
43
44 if (out == NULL) {
45 idx2 = blks * 4 ;
46 if (left_over)
47 idx2 += 4;
48 if (newline_flag)
49 idx2 += len / 57; // (NEWLINE_INVL / 4) * 3 = 57. One newline per 57 input bytes.
50 }
51 else {
52 // Since 3 input bytes = 4 output bytes, determine out how many even sets of
53 // 3 bytes the input has.
54 blk_ceiling = blks * 3;
55 for (idx = 0, idx2 = 0; idx < blk_ceiling; idx += 3, idx2 += 4) {
56 out[idx2] = charset[in[idx] >> 2];
57 out[idx2 + 1] = charset[((in[idx] & 0x03) << 4) | (in[idx + 1] >> 4)];
58 out[idx2 + 2] = charset[((in[idx + 1] & 0x0f) << 2) | (in[idx + 2] >> 6)];
59 out[idx2 + 3] = charset[in[idx + 2] & 0x3F];
60 // The offical standard requires a newline every 76 characters.
61 // (Eg, first newline is character 77 of the output.)
62 if (((idx2 - newline_count + 4) % NEWLINE_INVL == 0) && newline_flag) {
63 out[idx2 + 4] = '\n';
64 idx2++;
65 newline_count++;
66 }
67 }
68
69 if (left_over == 1) {
70 out[idx2] = charset[in[idx] >> 2];
71 out[idx2 + 1] = charset[(in[idx] & 0x03) << 4];
72 out[idx2 + 2] = '=';
73 out[idx2 + 3] = '=';
74 idx2 += 4;
75 }
76 else if (left_over == 2) {
77 out[idx2] = charset[in[idx] >> 2];
78 out[idx2 + 1] = charset[((in[idx] & 0x03) << 4) | (in[idx + 1] >> 4)];
79 out[idx2 + 2] = charset[(in[idx + 1] & 0x0F) << 2];
80 out[idx2 + 3] = '=';
81 idx2 += 4;
82 }
83 }
84
85 return(idx2);
86}
87
88size_t base64_decode(const BYTE in[], BYTE out[], size_t len)
89{
90 BYTE ch;
91 size_t idx, idx2, blks, blk_ceiling, left_over;
92
93 if (in[len - 1] == '=')
94 len--;
95 if (in[len - 1] == '=')
96 len--;
97
98 blks = len / 4;
99 left_over = len % 4;
100
101 if (out == NULL) {
102 if (len >= 77 && in[NEWLINE_INVL] == '\n') // Verify that newlines where used.
103 len -= len / (NEWLINE_INVL + 1);
104 blks = len / 4;
105 left_over = len % 4;
106
107 idx = blks * 3;
108 if (left_over == 2)
109 idx ++;
110 else if (left_over == 3)
111 idx += 2;
112 }
113 else {
114 blk_ceiling = blks * 4;
115 for (idx = 0, idx2 = 0; idx2 < blk_ceiling; idx += 3, idx2 += 4) {
116 if (in[idx2] == '\n')
117 idx2++;
118 out[idx] = (revchar(in[idx2]) << 2) | ((revchar(in[idx2 + 1]) & 0x30) >> 4);
119 out[idx + 1] = (revchar(in[idx2 + 1]) << 4) | (revchar(in[idx2 + 2]) >> 2);
120 out[idx + 2] = (revchar(in[idx2 + 2]) << 6) | revchar(in[idx2 + 3]);
121 }
122
123 if (left_over == 2) {
124 out[idx] = (revchar(in[idx2]) << 2) | ((revchar(in[idx2 + 1]) & 0x30) >> 4);
125 idx++;
126 }
127 else if (left_over == 3) {
128 out[idx] = (revchar(in[idx2]) << 2) | ((revchar(in[idx2 + 1]) & 0x30) >> 4);
129 out[idx + 1] = (revchar(in[idx2 + 1]) << 4) | (revchar(in[idx2 + 2]) >> 2);
130 idx += 2;
131 }
132 }
133
134 return(idx);
135}